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Home/ Questions/Q 9145577
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T10:32:57+00:00 2026-06-17T10:32:57+00:00

If I initialize a std::array as follows, the compiler gives me a warning about

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If I initialize a std::array as follows, the compiler gives me a warning about missing braces

std::array<int, 4> a = {1, 2, 3, 4};

This fixes the problem:

std::array<int, 4> a = {{1, 2, 3, 4}};

This is the warning message:

missing braces around initializer for 'std::array<int, 4u>::value_type [4] {aka int [4]}' [-Wmissing-braces]

Is this just a bug in my version of gcc, or is it done intentionally? If so, why?

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  1. Editorial Team
    Editorial Team
    2026-06-17T10:32:58+00:00Added an answer on June 17, 2026 at 10:32 am

    This is the bare implementation of std::array:

    template<typename T, std::size_t N>
    struct array {
        T __array_impl[N];
    };
    

    It’s an aggregate struct whose only data member is a traditional array, such that the inner {} is used to initialize the inner array.

    Brace elision is allowed in certain cases with aggregate initialization (but usually not recommended) and so only one brace can be used in this case. See here: C++ vector of arrays

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