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Home/ Questions/Q 6189279
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T02:23:37+00:00 2026-05-24T02:23:37+00:00

If I manually create an array with array = [2,1,3] array.sort will return a

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If I manually create an array with

array = ["2","1","3"]

array.sort will return a sorted version of the array.

But if I create an array by using

array2 = ["213".split(//)]

or

array2 = []
array2 << "213".split(//)

array2.sort will return the unsorted array.

Why doesn’t this work? Are the arrays created like that somehow different, and if yes, how?

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  1. Editorial Team
    Editorial Team
    2026-05-24T02:23:37+00:00Added an answer on May 24, 2026 at 2:23 am

    You define array2 as [“213”.split(//)]. This puts an array ([“2″,”1″,”3”]) inside an array. The output is:

    array = [“213”.split(//)]
    => [[“2”, “1”, “3”]]

    When you try and sort that, it sorts the “bigger” array: the one with one element!
    This works, though:

    array = “213”.split(//)
    => [“2”, “1”, “3”]
    array.sort
    => [“1”, “2”, “3”]

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