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Home/ Questions/Q 6120729
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T15:42:06+00:00 2026-05-23T15:42:06+00:00

If I run it in the command line, the program will stop after client.destroy();

  • 0

If I run it in the command line, the program will stop after client.destroy();

var client = http.get(options, 
        function(res) {
            console.log(res.statusCode);
            client.destroy();
          }
);

However, it is not the case when I put the client.destroy() inside the res.on(‘end’):

var client = http.get(options, 
        function(res) {
            console.log(res.statusCode);
            res.on('end', function() {
                console.log("done");
                client.destroy();
            });
          }
);

It will throw exception because the http.socket is null. so, I can’t destroy it.

IN this case, the program execution will hang there and will not end. What can I do to stop it? (other than process.exit());

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T15:42:07+00:00Added an answer on May 23, 2026 at 3:42 pm

    if it’s single request you can just set shouldKeepAlive to false

    var request = http.get(options, 
            function(res) {
                console.log(res.statusCode);
              }
    );
    request.shouldKeepAlive = false
    

    or send Connection: close header

    You can’t access socket because it is detached in the request ‘end’ event handler

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