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Home/ Questions/Q 6909567
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T08:42:23+00:00 2026-05-27T08:42:23+00:00

If I run the following code: BitSet test = new BitSet(20); System.out.println(Bitset size is

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If I run the following code:

BitSet test = new BitSet(20);
System.out.println("Bitset size is " + test.size());
System.out.println("Bitset length is " + test.length());

I get the output:

Bitset size is 64
Bitset length is 0

Which makes sense now that I look closer at the documentation (the former getting the size including implementation overhead and the latter being the last set bit, with all defaulting to false), but is not what I want.

Since the BitSet I actually use can have varying lengths, I want to be able to get back the number of bits represented (ignoring whether they are set). Is there a way to do that (hopefully with a built-in method)?

I realize I could try flipping all the bits and then doing length, or by tracking the variable I use to instantiate the BitSet, but I feel like both would require several lines of comments with my reasons and I was hoping for something a bit more self-documenting.

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  1. Editorial Team
    Editorial Team
    2026-05-27T08:42:23+00:00Added an answer on May 27, 2026 at 8:42 am

    A BitSet will automatically expand to a size sufficient to represent the highest bit set in it; the initial size is simply a hint as to how many bits you intend to use. So your question as posed makes no sense.

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