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Home/ Questions/Q 6842183
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T00:04:06+00:00 2026-05-27T00:04:06+00:00

If I run this: ‘121’.match(/[0-9]{2}/gi) I get back an array with a single result:

  • 0

If I run this:

'121'.match(/[0-9]{2}/gi)

I get back an array with a single result:

['12']

How can I get it to return all results, even if they overlap? I want the result to be this:

['12', '21']

EDIT: Or a better example would be:

'1234567'.match(...);

should give me an array with

[12,
23,
34,
45,
56,
67]

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T00:04:07+00:00Added an answer on May 27, 2026 at 12:04 am

    this just won’t work in the way you want.

    when you specify pattern [0-9]{2}, match() looks up first occurrence of two digit number, then continues search from that place on. as string length is 3, obviously it won’t find another match.

    you should use different algorithm for finding all two digit numbers. I would suggest using combination of your first match and do one more with following regex

    /[0-9]([0-9]{2})/ and combine sets of both first and second run.

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