Question

If I try to write a method like below

public void someStuff(Object ... args, String a )

I get this error

The variable argument type Object of the method someStuff must be the last parameter.

I don’t fully understand the requirement of variable argument type to be the last.
Any inputs will be helpful.

Answer 1

It follows the C convention. The C convention in turn is based on CPU architectures which pass arguments on the stack. The first non-vararg arguments end up at a fixed offset in the stackframe. If you could put the vararg arguments first, the stack offset of the following arguments would depend on how many vararg parameters you would have passed. This would greatly complicate the amount of code needed to access them.

In your example, with String a first, it’s conceptually at offset 0 independent how the number of vararg arguments that follow. But with String a last, it could be at offset 0, 4, 8, 12 etc – you’d have to calculate args.size * 4 everytime you needed String a.