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Home/ Questions/Q 7185951
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T18:31:43+00:00 2026-05-28T18:31:43+00:00

If I use a Matplotlib DateFormatter, like this: mydateformatter = DateFormatter(%b %d %I:%M %p,

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If I use a Matplotlib DateFormatter, like this:

mydateformatter = DateFormatter("%b %d %I:%M %p", self._tz)

I’ll get dates like (note the time part has a leading zero):

Nov 27 2011
03:00 PM

Instead, I’d like to lose the leading zero on times (more human that way), like:

Nov 27 2011
3:00 PM

Is there a way to do that?

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  1. Editorial Team
    Editorial Team
    2026-05-28T18:31:44+00:00Added an answer on May 28, 2026 at 6:31 pm

    Note: see the edit history to understand the discussion in the comments below. This post has been rewritten to reflect them.

    It can’t be done using the standard date conversion specifiers, which are listed in the python docs (the same ones as standardized by C). However, there may be platform dependent ways to accomplish this format. A bit of code like this might come in handy:

    # Set the default spec to use -- uglier is better than broken.
    hour_fmt = '%I'
    
    # If we're running on a platform that has an hour spec w/o leading zero
    # then use that one instead.
    if sys.platform.startswith('linux'):
        hour_fmt = '%l'
    elif sys.platform.startswith('win'):
        hour_fmt = '%#I'
    # etc
    
    mydateformatter = DateFormatter("%b %d " + hour_fmt + ":%M %p", self._tz)
    

    I have confirmed %l to work on Linux and the OP has confirmed ‘%#I` to work on Windows.

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