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Home/ Questions/Q 6873077
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T04:00:44+00:00 2026-05-27T04:00:44+00:00

If I want to convert Range to Set I can write (0 to 9).toSet

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If I want to convert Range to Set I can write

(0 to 9).toSet

What if I need to convert Range to SortedSet? I can write something like:

scala.collection.immutable.SortedSet[Int]((0 to 9): _*)
scala.collection.immutable.SortedSet[Int]() ++ (1 to 9)

Does it make sense? Is there any “better” (efficient/simple) way to convert Range to SortedSet?

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  1. Editorial Team
    Editorial Team
    2026-05-27T04:00:45+00:00Added an answer on May 27, 2026 at 4:00 am

    What could possibly be more simple than this? (You don’t need the type parameter or the extra parentheses.)

    SortedSet(0 to 9:_*)
    

    It should also be reasonably efficient.

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