Question

If I want to create a function template, where the template parameter isn’t used in the argument list, I can do it thusly:

template<T>
T myFunction()
{
//return some T
}

But the invocation must specify the ‘T’ to use, as the compiler doesn’t know how to work it out.

myFunction<int>();

But, suppose I wanted to do something similar, but for the ‘[]’ operator.
template

T SomeObject::operator [ unsigned int ]
{
    //Return some T
}

Is there any way to invoke this operator?
This doesn’t appear valid:

SomeObject a;
a<int>[3];

Answer 1

This should work:

class C
{
public:
    template <class T>
    T operator[](int n)
    {
        return T();
    }
};

void foo()
{
    C c;

    int x = c.operator[]<int>(0);
}

But it’s of no real value because you’d always have to specify the type, and so it looks like a very ugly function call – the point of an operator overload is to look like an operator invocation.