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Home/ Questions/Q 8678527
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T20:44:38+00:00 2026-06-12T20:44:38+00:00

If I want to estimate a level-log regression by OLS, I do that because

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If I want to estimate a level-log regression by OLS, I do that because I believe that my x value (the independend variable) displays a diminishing marginal return on my y value (the dependend variable).

For example hours = beta0 + beta1*log(wage)
where
hours = hour worked per week
wage = hourly wage

Then OLS fits a linear line.
To interpret my beta1 cofficient I divide it by 100 by saying a 1 % increase in wage has a XX effect on hours worked per week.

But from my estimated beta1 cofficient, how can I see the diminishing effect the independend variable has on the dependend now that it is a linear line?

Suddenly after the estimation I cannot see how I can interpret this constant to be a diminishing effect on the dependend variable?

Kind Regards Maria

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  1. Editorial Team
    Editorial Team
    2026-06-12T20:44:40+00:00Added an answer on June 12, 2026 at 8:44 pm

    This should have been posted into the stat version of StackOverflow.
    Anyways my suggestion is to try this (start with a basic linear model):

    1) Check the plot of the residuals. If there is no sign of heteroscedasticity in the linear model, then stop. Otherwise if you can see a pattern in the residuals (funnel, sinusoids or anything else) continue. -> E[sigma_i]!=sigma for i=1..k where k = model dimensions.

    2) Try with a squared model. In this case I would do:

    Y = beta[0]+beta[1]*X+beta[2]*X^2
    

    Then if your ideas are correct you should get a positive beta[1] and a negative beta[2]. Most likely with abs(beta[1])>abs(beta[2]). This mean that with for small value or X the effect of the squared component (negative) will be little to none, while with for a big value of X the negative squared component will be very strong.
    Now go back to 1) if you get normal residuals you are done.

    3) Try with:

    Y = beta[0]+beta[1]*log(X)
    

    and with:

    Y = beta[0]+beta[1]*log(X^2)
    

    And see which one gives you the best residuals.

    There is only one issue in your reasoning. You don’t have anymore a linear line, but a curve, as denoted by the relationship Y = b*LN(X). Therefore the log curve itself explains your “diminishing returns”.

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