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Home/ Questions/Q 6945335
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T13:25:23+00:00 2026-05-27T13:25:23+00:00

If I wanted to create an expression tree that called a method with an

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If I wanted to create an expression tree that called a method with an out parameter and then returned the out value as a result.. how would I go about it?

The following does not work (throws a runtime exception), but perhaps best demonstrates what I’m trying to do:

private delegate void MyDelegate(out int value);
private static Func<int> Wrap(MyDelegate dele)
{
    MethodInfo fn = dele.Method;
    ParameterExpression result = ParameterExpression.Variable(typeof(int));
    BlockExpression block = BlockExpression.Block(
        typeof(int), // block result
        Expression.Call(fn, result), // hopefully result is coerced to a reference
        result); // return the variable
    return Expression.Lambda<Func<int>>(block).Compile();
}

private static void TestFunction(out int value)
{
    value = 1;
}

private static void Test()
{
    Debug.Assert(Wrap(TestFunction)() == 1);
}

I know this can be fairly easily solved in raw IL (or indeed without runtime compilation at all), but unfortunately this is part of a much larger expression building process… so I’m really hoping this isn’t a limitation, as a complete rewrite would be more than a bit of a pain.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T13:25:24+00:00Added an answer on May 27, 2026 at 1:25 pm

    This works for me:

        private static Func<int> Wrap(MyDelegate dele)
        {
            var fn = dele.Method;
            var result = ParameterExpression.Variable(typeof(int));
            var block = BlockExpression.Block(
                typeof(int),
                new[] { result },
                new Expression[]
                {
                    Expression.Call(fn, result),
                    result,
                });
            return Expression.Lambda<Func<int>>(block).Compile();
        }
    
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