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Home/ Questions/Q 6110241
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T14:29:35+00:00 2026-05-23T14:29:35+00:00

If I were to wanted to parameterize creating an object, I could of course

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If I were to wanted to parameterize creating an object, I could of course make a function which called new on a particular class and passed out a pointer. I am wondering if it’s possible to skip that step and pass a function pointer to the new operator itself.

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  1. Editorial Team
    Editorial Team
    2026-05-23T14:29:36+00:00Added an answer on May 23, 2026 at 2:29 pm

    boost::lambda provides function wrappers for new and delete. These can be used to easily convert an new call into a function object.

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