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Home/ Questions/Q 6105575
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T13:59:10+00:00 2026-05-23T13:59:10+00:00

If I wish to use dynamic_cast with a shared_ptr I can use dynamic_pointer_cast .

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If I wish to use dynamic_cast with a shared_ptr I can use dynamic_pointer_cast. What do I use if I wish to cast an auto_ptr? I’m assuming something that would look like below.

struct B : A { };
...
auto_ptr<A> base( ... );
auto_ptr<B> derive = dynamic_pointer_cast<B>(base);

I’m using boost for shared_ptr’s

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T13:59:10+00:00Added an answer on May 23, 2026 at 1:59 pm
    auto_ptr<A> base( ... );
    if(B* query = dynamic_cast<B>(base.get())) {
        // take ownership
        base.release();
        auto_ptr<B> derived(query);
    
        // use and/or pass derived around here
        // ...
    } else {
        // no dice: leave base as owner
    }
    

    Since you’re already doing that, then refactor it, slap it in the namespace of your choice and call it a day:

    // Postcondition:
    // where r is the returned pointer and p == from.get()
    // EITHER r == 0 AND from.get() == p
    // OR r.get() == dynamic_cast<To>(p) AND from == 0
    template<typename To, typename From>
    std::auto_ptr<To>
    dynamic_pointer_cast(std::auto_ptr<From>& from)
    {
        To* query = dynamic_cast<To>(from.get());
        return query ? from.release(), query : 0;
    }
    
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