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Home/ Questions/Q 7016073
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T22:44:13+00:00 2026-05-27T22:44:13+00:00

If I write: def getShort(b: Array[Byte]): Short in Scala, I get a primitive short

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If I write:

def getShort(b: Array[Byte]): Short

in Scala, I get a primitive short in Java, which is fine. But if I write:

def getChar(b: Array[Byte]): Char

I get a scala.Char object, which is NOT fine. And if I write:

def getChar(b: Array[Byte]): Character

I get a java.lang.Character, which ISN’T fine either.

If Scala “Char” isn’t Java “char”, and Scala “Character” isn’t Java “char”, then what is left?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T22:44:13+00:00Added an answer on May 27, 2026 at 10:44 pm

    You’re mistaken; Char is the Java primitive char. Observe:

    scala> class IsPrimitiveChar {
         |   def myChar(i: Int): Char = i.toChar   // I am clearly a Char, whatever that is!
         | }
    defined class IsPrimitiveChar
    
    scala> :javap IsPrimitveChar
    Compiled from "<console>"
    public class IsPrimitiveChar extends java.lang.Object implements scala.ScalaObject{
        public char myChar(int);  // Look, it returns a char!
        public IsPrimitiveChar();
    }
    
    
    scala> :javap -c -private IsPrimitiveChar
    Compiled from "<console>"
    public class IsPrimitiveChar extends java.lang.Object implements scala.ScalaObject{
    public char myChar(int);
      Code:
       0:   iload_1
       1:   i2c               // Look, primitive int to char conversion in bytecode!
       2:   ireturn           // And that's all!
    

    One needs to have tools.jar on the classpath for :javap to work, by the way. It’s included with the Sun/Oracle JVMs.

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