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Home/ Questions/Q 7690709
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T20:27:29+00:00 2026-05-31T20:27:29+00:00

If it is not possible to create this list without loops, I’d be content

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If it is not possible to create this list without loops, I’d be content just to minimize the time it takes to create this list. The goal is to create a two-dimensional array with the filenames for 100 pdf files in each of 10 or so folders. Tell me what you think:

    foldernames = [ 
        'Named_folder00/',
        'Named_folder01/',
        'Named_folder02/',
        'Named_folder03/',
        'Named_folder04/',
        'Named_folder05/',
        'Named_folder06/',
        'Named_folder07/',
        'Named_folder08/',
        'Named_folder09/',
        ]

    pages = []
    for b in xrange(len(foldernames)):
        pg_temp = [
            foldernames[b] + 'title1',
            foldernames[b] + 'title2',
            foldernames[b] + 'title3'
            ]
        pg_temp += [ foldernames[b] + '0' + str(j) for j in xrange(1,10) ]
        pg_temp += [ foldernames[b] + str(k) for k in xrange(10,100) ]
        for c in xrange(len(pg_temp)):
            pg_temp[c] += '.pdf'
        pages.append(pg_temp)
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T20:27:30+00:00Added an answer on May 31, 2026 at 8:27 pm
    files = ['title1.pdf', 'title2.pdf', 'title3.pdf']
    files += [ "%.2d.pdf" % j for j in range(1,100)]
    pages = [[folder+file for file in files] for folder in foldernames]
    

    Note: I have no idea how fast it is, didn’t benchmark it.

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