Question

If i’ve database table with users(name,job) (john,Poster) and i made query with MySQLi using this code and that would works.

$job = "Poster";

$statement = $con->prepare("SELECT * FROM users WHERE `job` =  ?");
$statement->bind_param("s",$job);
$statement->execute();
$statement->bind_result($name,$job);

while ($statement->fetch()){
echo $name;
}

what if i made $job = "NOTHING"; and there was no results then how can i show error such as echo "No reuslts found"; !! the above code if $job was not found it will show nothing. ~ thanks

EDIT
this one didn’t worked too 🙁

$job = "NOTHING"; // should not found and should gives error

if ($statement = $con->prepare("SELECT * FROM users WHERE `job` =  ?")){
$statement->bind_param("s",$job);
$statement->execute();
$statement->bind_result($name,$job);

while ($statement->fetch()){
echo $name;
}

}else{
echo "No results found dude";
}

Answer 1

Do not use mysqli. It is unusable with prepared statements.
Use PDO instead.

With PDO your code would be shorter, sensible and works.

$statement = $con->prepare("SELECT * FROM users WHERE `job` =  ?");
$statement->execute(array($job));
if ($row = $statement->fetch()){
    echo $row['name'];
} else {
    echo "No results found dude";
}

You need to create a connection first. Something like this

$dsn  = 'mysql:dbname=test;host=127.0.0.1';
$user = 'dbuser';
$pass = 'dbpass';
$con  = new PDO($dsn, $user, $pass);

You can see details on the manual page

As a further step you can move to some helper library, which will make your code even shorter:

$name = $db->getOne("SELECT name FROM users WHERE job=?s",$job);
if ($name) {
    echo $name;
} else {
    echo "No results found dude";
}

But it would be wise to get yourself familiar with raw API functions first.