Question

                if (password1.length() >= 15){          
                    final String PasswordPattern = "^(?=.*[0-9])(?=.*[A-Z])(?=.*[a-z])[0-9A-Za-z]{15,}$";

                    Pattern pattern = Pattern.compile(PasswordPattern);
                    Matcher matcher = pattern.matcher(password1);   

                    if(matcher.matches() == true){                      

                        if (password1.equals(password2)){
                            SavePreferences(password1.toString());
                            //Intent intent = new Intent(LockAppActivity.this, ScreenLockActivity.class);
                            Intent intent = new Intent(LockAppActivity.this, PhoneNumActivity.class);
                            startActivity(intent);
                        }
                        else{
                            pass1.setText("");
                            pass2.setText("");
                            Toast.makeText(LockAppActivity.this,"Both passwords are not equal!",Toast.LENGTH_SHORT).show();
                        }
                    }

I want user to enter password with at least 15 characters which must consists of Capital and Small letters, numbers and symbols. But I only know how to create pattern with Capital and Small letters and numbers… How can I include all the symbols in the pattern… Kindly check on my pattern code part… thanks

Answer 1

You could add the section (?=.*(\W|_)) to check for anything except alphanumeric (A-Z, a-z, 0-9) symbols. Or, you could specify a set of symbol characters like (?=.*[\.\*]). If you do, replace the contents of the [] with all the characters you want to allow, using a backslash before each character that has a regex function. (The example shows a section that allows two characters, . and *.)

Then you’ll need top update the section that counts the number of occurrences. Since we’re dealing with all characters now, we can replace the [0-9A-Za-z] with ., leaving us with: ^(?=.*[0-9])(?=.*[A-Z])(?=.*[a-z])(?=.*(\W|_)).{15,}$. Replace the single \ with two \\ since you’re placing this in a Java string.

Remember that Android keypads can vary, so not all of them are guaranteed to have the same symbols.