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if (phpversion() >= '4.3.0'){
$string = mysqli_real_escape_string($string);
}else{
$string = mysqli_escape_string($string);
}
All the documentation for mysqli_real_escape_string seems to indicate this is a valid bit of code, but I don’t understand why I get this error:
mysqli_real_escape_string() expects exactly 2 parameters, 1 given
Documentation says it needs two parameters:
The first one is a link for a mysqli instance, the second one is the string to escape.