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Home/ Questions/Q 6063563
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T09:10:47+00:00 2026-05-23T09:10:47+00:00

{% if posts %} {% for p in posts %} {{p|safe}} {% endfor %}

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{% if posts %}
    {% for p in posts %}
        {{p|safe}}
    {% endfor %}
{% endif %}

I want this to render html but not javascript, what should I do?

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  1. Editorial Team
    Editorial Team
    2026-05-23T09:10:48+00:00Added an answer on May 23, 2026 at 9:10 am

    There is no filter in django that can do what ou want: strip javascript and leave html.

    You can create a custom template filter to do that:

    from django import template
    from django.template.defaultfilters import stringfilter
    from django.utils.safestring import mark_safe
    from django.utils.encoding import force_unicode
    import re
    
    register = template.Library()
    
    @register.filter
    @stringfilter
    def stripjs(value):
        stripped = re.sub(r'<script(?:\s[^>]*)?(>(?:.(?!/script>))*</script>|/>)', \
                          '', force_unicode(value), flags=re.S)
        return mark_safe(stripped)
    

    (Where to put template filters/tags: Custom template tags and filters/Code layout)

    Brief explanation:

    Create a folder named templatetags in your application folder. Add an empty file __init__.py (for it to be a package) and a module file that will contain the filter, my_filters.py. Copy the code in that file.

    In the template file add (before any first use of the filter): {% load my_filters %}

    Usage:

    {% if posts %}
        {% for p in posts %}
            {{ p|stripjs }}
        {% endfor %}
    {% endif %}
    
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