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Home/ Questions/Q 6917953
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T09:47:49+00:00 2026-05-27T09:47:49+00:00

If subclassing a class in JavaScript is done like so: var ParentClass = function()

  • 0

If subclassing a “class” in JavaScript is done like so:

var ParentClass = function() {
    // something
};


var ChildClass = function() {
    // something
};

ChildClass.prototype = new ParentClass();

… what should I do when the parent class has required parameters?

var ParentClass = function(requiredParameter) {
    if (typeof requiredParameter === 'undefined') {
        throw new TypeError("'requiredParameter' is required!");
    }
};


var ChildClass = function() {
    // something
};

ChildClass.prototype = new ParentClass();
// ^ Throws TypeError

Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T09:47:51+00:00Added an answer on May 27, 2026 at 9:47 am

    Subclass it like this instead:

    function clone (obj) {
      if (!obj) return;
      clone.prototype = obj;
      return new clone();
    }
    
    var ParentClass = function() {
        // something
    };
    
    
    var ChildClass = function() {
        // something
    };
    
    ChildClass.prototype = clone(ParentClass.prototype);
    ChildClass.prototype.constructor = ChildClass; // if you want
    

    Now you don’t have to worry about it, because you don’t have to call the parent constructor to subclass it 🙂

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