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Home/ Questions/Q 7403521
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T05:06:22+00:00 2026-05-29T05:06:22+00:00

If the value in my control only have one value the following code will

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If the value in my control only have one value the following code will return a String, if there are more than one value the code will return a java.util.Vector.

getComponent(“mycontrol”).getValue();

I want this code to return a vector even if there is only one value.

I have seen several code snippets that converts my string to an Array, but I want to get back a vector.

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  1. Editorial Team
    Editorial Team
    2026-05-29T05:06:24+00:00Added an answer on May 29, 2026 at 5:06 am

    There is no way to force a singular value to be returned as a java.util.vector (or Array for that matter). The only way would be to test to see if it is a vector, then build a vector if not. You could place it into a function and wrap the call into that… for example (this is untested code so you’ll need to verify syntax, etc):

    asVector(getComponent("mycontrol").getValue());
    
    function asVector(obj) {
      if (obj.constructor === java.util.Vector) {
        return obj;
      } else {
        var x:java.util.Vector = new java.util.Vector();
        x.add(obj);
        return x;
      }
    }
    
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