Question

if we have a 1D array, we could use the following to see if all elements are equal to 3:

int[] t = Enumerable.Repeat(3, 10).ToArray();

if (t.All(item => item.Equals(3))) MessageBox.Show("all elements equals to 3");

but if I have a 2D-array, how could I check if all elements are equal to 3 ( without any for-Loops ):

    int[,] t2D= new int[,] { { 3, 3 }, { 3, 3 }, { 3, 3 }, { 3, 3 } };

    if( CHECK IF ALL ELEMENTS IN **t2D** are equal to 3) 

               {
                MessageBox.Show("all elements equals to 3");
               }

What should I put in If-statement?

Answer 1

2D-array is an enumerable type (but it implements non-generic IEnumerable). And it’s enumerator enumerates over all items in 2D-array. So, only thing you need to do – cast its items to int (thus retrieving IEnumerable<int>) and apply All

t2D.Cast<int>().All(x => x == 3)