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Home/ Questions/Q 5983933
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T22:18:07+00:00 2026-05-22T22:18:07+00:00

If you run the following Groovy code, the assertion passes def foo(a, b) {

  • 0

If you run the following Groovy code, the assertion passes

def foo(a, b) {
  a + b
}

assert 'aaabbb' == foo(['aaa', 'bbb'])

This suggests that if a method is called with a List parameter that contains X elements, then the List will be spread and a method with X arguments will be invoked.

Of course, this will only happen if there isn’t a method defined with a single parameter of type List (or ancestor thereof).

I only discovered this quite recently when reading another SO Groovy answer. I’ve never seen it mentioned in the Groovy docs, release notes, or books. Is it a hidden feature, a bug, or just something I’ve missed?

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  1. Editorial Team
    Editorial Team
    2026-05-22T22:18:08+00:00Added an answer on May 22, 2026 at 10:18 pm

    Going to be removed in Groovy 2 apparently:
    http://groovy.329449.n5.nabble.com/removing-features-in-Groovy-2-td4422494.html

    JT’s first on the to-remove list and it seems everyone (with clout) on Groovy User agrees.

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