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Home/ Questions/Q 123959
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Editorial Team
Asked: May 11, 20262026-05-11T04:22:11+00:00 2026-05-11T04:22:11+00:00

If you scan a folder containing other folders AND files, how do you get

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If you scan a folder containing other folders AND files, how do you get rid of . and .. and files? How do you put in array only folders WITHOUT . and ..? I would like to use regular expression, but I’m newbie and I can’t get it right. My code is now this but doesn’t work:

if(fnmatch(‘\.{1,2}’,$dir_array[$i]) || is_file($dir_array[$i]){
unset($dir_array[$i]);
}else{ //other code
}

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  1. 2026-05-11T04:22:11+00:00Added an answer on May 11, 2026 at 4:22 am

    You are confusing fnmatch and regular expressions in your code. To get all files and directories except the special ones, use this:

    $dir_array = array_diff($dir_array, array('.', '..')); 

    Alternatively, if you iterate the array anyway, you can test each element like this:

    foreach ($dir_array as $name) {     if (($name != '..') && ($name != '.')) {         // Do stuff on all files and directories except . ..         if (is_dir($name)) {             // Do stuff on directories only         }     } } 

    In php<5.3, you can exclusively use a callback function, too:

    $dir_array = array_filter($dir_array,   create_function('$n', 'return $n != '.' && $n != '..' && is_dir($n);')); 

    (See Allain Lalonde’s answer for a more verbose version)

    Since php 5.3, this can be written nicer:

    $dir_array = array_filter($dir_array,   function($n) {return $n != '.' && $n != '..' && is_dir($n);}); 

    Finally, combining array_filter and the first line of code of this answer yields an (insignificantly) slower, but probably more readable version:

    $dir_array = array_filter(array_diff($dir_array, array('.', '..')), is_dir); 
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