Question

If you’re implementing a subclass, you can, within your implementation, explicitly call the superclass’s method, even if you’ve overridden that method, i.e.:

[self overriddenMethod]; //calls the subclass's method
[super overriddenMethod]; //calls the superclass's method

What if you want to call the superclass’s method from somewhere outside the subclass’s implementation, i.e.:

[[object super] overriddenMethod]; //crashes

Is this even possible? And by extension, is it possible to go up more than one level within the implementation, i.e.:

[[super super] overriddenMethod]; //will this work?

Answer 1

A more pleasant option (for debugging) is to add a category method which does it for you:

- (void) callSuperMethod { [super overriddenMethod]; }

The fact that there’s no more convenient way to do this is very much by design.