Question

#ifndef UNICODE 
#define UNICODE
#endif

#include <stdlib.h>
#include <stdio.h>
#include <time.h>
#include <Windows.h>

int main()
{
    char buffer[30];
    int counter=0;

    for(int i=0; i<22 ; i++)
    {       
        Sleep(1000);
        printf("%d %d\n",counter++,time(0));
    }

    system("pause");
    return 0;
}

This version works fine, it outputs counter and the timestamps of the last 22 seconds. Unfortunately, when I did seemingly extraneous thing – replacing counter and time(0) , that is printf("%d %d\n",time(0),counter++); , function always printed 0 in place of counter! Any explanation of this strange fact?

Answer 1

The result of time() (on Windows at least) is a 64-bit integer. You must use a format other than %d to print it. Try %lld.

It worked when the time was last because you got the lower 32 bits, since Intel is a little-endian processor.