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Home/ Questions/Q 9128723
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T07:34:54+00:00 2026-06-17T07:34:54+00:00

I’ll admit, I don’t know tons about MySQL queries or JSON for that matter

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I’ll admit, I don’t know tons about MySQL queries or JSON for that matter but I would like to. Currently when I get data from my database I query one table which brings values into another query and so on. I don’t think this is the best practice to go about receiving all the data I need to display. Below is an example of how my MySQL queries currently work in a PHP foreach function:
enter image description here

So, is there a better way of completing the query(s) I want and how would I be able to encode it as JSON?

Any help would be appreciated, thank you.

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  1. Editorial Team
    Editorial Team
    2026-06-17T07:34:55+00:00Added an answer on June 17, 2026 at 7:34 am

    From what I understand, your code is doing something like this:

    <?php
    $friends = query("SELECT Friends");
    while($row = fetch_object($friends)){
        $friend_dets = query("SELECT Friend_dets WHERE Friend_ID = $row->Friend_ID");
        $output[] = fetch_assoc($friend_dets);
    }
    echo json_encode($output);
    ?>
    

    With this, you’re making the process more complex than it needs to be. You can get all of the information you need with one query with a JOIN like this:

    SELECT Name, Status, WhateverElseYouWant
    FROM Friends
        JOIN Profiles ON (Friends.friend-profile-id = Profiles.profile-id)
    WHERE Friends.profile-id = MyCurrentProfileID
    

    That will give you the name, status and whatever else of everyone who is friends with MyCurrentProfileID. Then, you just need to put the result in an array and json_encode it:

    <?php
    $friends = query($QueryFromAbove);
    while($row = fetch_object($friends)){
        $output[] = fetch_assoc($friend_dets);
    }
    echo json_encode($output);
    ?>
    
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