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Home/ Questions/Q 1072477
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T20:51:58+00:00 2026-05-16T20:51:58+00:00

I’ll appreciate if anyone can explain the logic behind protocol inheritance. e.g. what does

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I’ll appreciate if anyone can explain the logic behind protocol inheritance. e.g. what does the following mean (UITableView.h):

@protocol UITableViewDelegate<NSObject, UIScrollViewDelegate> 

The following class implementation doesn’t work. I have a class View1 (which inherits UIView), with an associated protocol. I have another class, View2 (which inhertits View1). Now i want to inherit the the protocol as well. Can anyone please point me in the right direction.

Class 1:

@protocol View1Delegate;

@interface View1 : UIView {
    id <View1Delegate> delegate;
    // . . .
}

@property (nonatomic, assign) id <View1Delegate> delegate; // default nil. weak reference

@end

@protocol View1Delegate <NSObject>
- (void)View1DelegateMethod;
@end

@implementation View1

@synthesize delegate;

// . . .
@end

Class 2:

@protocol View2Delegate;

@interface View2 : View1 {
    id <View2Delegate> delegate;
    // . . .
}

@property (nonatomic, assign) id <View2Delegate> delegate; // default nil. weak reference

@end

@protocol View2Delegate <NSObject>
- (void)View2DelegateMethod;
@end

@implementation View2

@synthesize delegate;

// . . .
@end
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  1. Editorial Team
    Editorial Team
    2026-05-16T20:51:59+00:00Added an answer on May 16, 2026 at 8:51 pm

    Think of it more as composition rather than inheritance.

    @protocol UITableViewDelegate<NSObject, UIScrollViewDelegate> defines a protocol that includes all the methods of the NSObject protocol, the UIScrollViewDelegate protocol, as well as any methods defined for the UITableViewDelegate protocol. When you subclass and create a new property, you’re overriding the type of the superclasses property. To make this work how I think you want, you should declare View2Delegate as @protocol View2Delegate <NSObject, View1Delegate>.

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