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Asked: 2026-05-10T22:01:14+00:00

I’ll be using the AdventureWorks Database to illustrate my problem. I need to show

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I’ll be using the AdventureWorks Database to illustrate my problem.

I need to show for a particular customer a list of OrderDate with the most Orders.

My intial attempt was as follows:

SELECT CustomerID, OrderDate, COUNT(1) Cnt FROM Sales.SalesOrderHeader WHERE CustomerID = 11300 GROUP BY CustomerID, OrderDate ORDER BY Cnt DESC

This will get us the following result:

CustomerID    OrderDate             Cnt -----------   ----------                ---- 11300        2003-11-22 00:00:00.000     2 11300        2004-01-28 00:00:00.000     2 11300        2004-02-18 00:00:00.000     2 11300        2004-02-08 00:00:00.000     2 11300        2004-02-15 00:00:00.000     1 11300        2004-03-11 00:00:00.000     1 11300        2004-03-24 00:00:00.000     1 11300        2004-03-30 00:00:00.000     1 11300        2004-04-28 00:00:00.000     1 11300        2004-05-03 00:00:00.000     1 11300        2004-05-17 00:00:00.000     1 11300        2004-06-18 00:00:00.000     1 ...

Not exactly what I wanted, as the result should only show all records where Cnt = 2, like so:

CustomerID    OrderDate             Cnt -----------   ----------                ---- 11300        2003-11-22 00:00:00.000     2 11300        2004-01-28 00:00:00.000     2 11300        2004-02-18 00:00:00.000     2 11300        2004-02-08 00:00:00.000     2

I’m stuck because I can’t wrap my mind around two problems:

1) A customer might have more than one OrderDate with the same Cnt value. This means I can’t do something like TOP 1 to get the desired result.
2) Because the number of Orders for each customer may be different, I cannot use the following SQL statement:

SELECT CustomerID, OrderDate, COUNT(1) Cnt FROM Sales.SalesOrderHeader WHERE CustomerID = 11300 GROUP BY CustomerID, OrderDate HAVING COUNT(1) > 1 ORDER BY Cnt DESC

This will work for getting the right result for this customer, but will definitely be wrong if the next customer has only one Order for a particular day.

So, either the query is impossible in this situation, or I am approaching the query in the wrong way. Any ideas on this problem is appreciated.

Also, since this will be a query in a stored procedure, any ideas on solving this in T-SQL will be acceptable.

UPDATE: Thanks to Mehrdad, I’ve been introduced to Common Table Expressions, and Life is Good®. 🙂

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1 Answer

  1. You should use TOP n WITH TIES clause to accomplish the task:

    SELECT TOP 1 WITH TIES CustomerID, OrderDate, COUNT(*) Cnt FROM Sales.SalesOrderHeader WHERE CustomerID = 11300 GROUP BY CustomerID, OrderDate ORDER BY Cnt DESC

    Alternatively, you can use a common table expression (CTE) to solve the problem. This solution requires SQL Server 2005 or higher:

    WITH MyTable AS (SELECT CustomerID, OrderDate, COUNT(*) Cnt                  FROM Sales.SalesOrderHeader                  WHERE CustomerID = 11300                  GROUP BY CustomerID, OrderDate) SELECT CustomerID, OrderDate, Cnt FROM MyTable WHERE Cnt = (SELECT MAX(Cnt) FROM MyTable);

    If you’re using the CTE method, make sure the previous statement is terminated by a semicolon (if it’s not the first statement). It’s required before a CTE expression.

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