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Home/ Questions/Q 8005045
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T17:06:24+00:00 2026-06-04T17:06:24+00:00

I’m a bit confused about the difference between when I just declare a variable

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I’m a bit confused about the difference between when I just declare a variable such as:

int n;

and dynamically assigning memory to a variable using “new” such as:

int m = new int;

I noticed just from working on a simple linked list project that when I’m inserting a new value in the form of an node object, I have to dynamically create a new node object and append the desired value to it and then link it to the rest of my list. However.. in the same function, I could just define another node object, ex. NodeType *N. and traverse my list using this pointer.
My question is.. when we just declare a variable, does memory not get assigned right away.. or what’s the difference?

Thank you!

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  1. Editorial Team
    Editorial Team
    2026-06-04T17:06:26+00:00Added an answer on June 4, 2026 at 5:06 pm

    Prefer automatic storage allocated variables when possible:

    int n;
    

    over

    int* m = new int; // note pointer
    

    The reason dynamic allocation is prefered in your case is the way the linked list is defined. I.e. each node contains a pointer to a next node (probably). Because the nodes must exist beyond the point where they are created, they are dynamically allocated.

    NodeType *N. and traverse my list using this pointer

    Yes, you could do that. But note that this is just a pointer declaration. You have to assign it to something meaningful to actually use it.

    My question is.. when we just declare a variable, does memory not get assigned right away.. or what’s the difference?

    Actually, both cases are definitions, not just declarations.

    int n;
    

    creates an un-initialized int with automatic storage;

    int* n;
    

    creates a pointer to an int. It’s dangling, it doesn’t point to a valid memory location.

    int* n = new int;
    

    creates a pointer and initializes it to a valid memory location containing an uninitialized int.

    int* n = new int();
    

    creates a pointer and initializes it to a valid memory location containing a value-initialized int (i.e. 0).

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