Question

I’m a bit new to scala and trying to test some stuff for my company.
My Problem is the following:
There’s a Scala class Test:

class Test {

  var id: Int = 0

}

Doing javap -private -c Test:

Compiled from "Test.scala"
public class com.example.Test extends java.lang.Object implements scala.ScalaObject{
private int id;

public int id();
  Code:
   0:   aload_0
   1:   getfield        #11; //Field id:I
   4:   ireturn

public void id_$eq(int);
  Code:
   0:   aload_0
   1:   iload_1
   2:   putfield        #11; //Field id:I
   5:   return

public com.example.Test();
  Code:
   0:   aload_0
   1:   invokespecial   #19; //Method java/lang/Object."<init>":()V
   4:   aload_0
   5:   iconst_0
   6:   putfield        #11; //Field id:I
   9:   return

}

As you can see, the id variable itself is marked as private. How can I force Scala to mark it as protected? There’s really no way round…

Answer 1

Because of the uniform access principle, all fields are private in Scala. But the generated methods aren’t. So you can do in Java:

Test test = new Test();
test.id_$eq( 23 );
System.out.println( test.id() ); //Should print "23"

If you find it ugly, you can use Java Beans accessors.