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Home/ Questions/Q 396307
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T16:32:22+00:00 2026-05-12T16:32:22+00:00

I’m a bit stuck on the last step of getting the solution to problem

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I’m a bit stuck on the last step of getting the solution to problem 2 on Project Euler. This is the source I’ve gotten so far.

#light
module pe2 (* Project Euler Problem 2 solution *)

  open System

  let Phi = 1.6180339887;;

  let invPhi = 1.0/Phi;;

  let rootOfFive = 2.236067977;;

  let maxFib = 4000000.0;

  let Fib n =
     System.Math.Round((Phi**n - invPhi**n)/rootOfFive);;

  let FibIndices = Seq.unfold(fun i -> Some(i, i+3.0)) 3.0;;

  let FibNos = FibIndices |> Seq.map(fun index -> Fib(index));;

  let setAllowedFibNos = FibNos |> Seq.filter(fun fn -> (fn <= maxFib));;

//   let answer = setAllowedFibNos |> Seq.fold (+) 0.0;

When I uncomment the last line, the process never seems to finish. So I was hoping that someone could give me a gentle nudge in the right direction. I did look at setAllowedFibNos and it looks right but it’s also an infinite sequence so I only see the first three terms.

Also, could someone point me to the right way to chain the various sequences together? I tried something like this:

let answer = Seq.unfold(fun i-> Some(i, i + 3.0)) 3.0 
|> Seq.map (fun index -> Fib(index))
|> Seq.filter(fun fn -> (fn <= maxFib))
|> Seq.fold (+) 0.0;;

But that didn’t work. As you can probably guess I’m just learning F# so please go gentle and if this sort of question has been asked and answered before, please post a link to the answer and I’ll withdraw this one.

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  1. Editorial Team
    Editorial Team
    2026-05-12T16:32:22+00:00Added an answer on May 12, 2026 at 4:32 pm

    ‘setAllowedFibNos’ is indeed an infinite seq computation; ‘fold’ needs the whole sequence, so the ‘filter’ will run forever looking for another number <= maxFib.

    Take a look at takeWhile:

    http://research.microsoft.com/en-us/um/cambridge/projects/fsharp/manual/FSharp.Core/Microsoft.FSharp.Collections.Seq.html

    I think it is what you want instead of filter.

    Also note that you can use ‘sqrt 5.0’.

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