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Editorial Team
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Asked: 2026-06-03T09:16:43+00:00

(I’m a complete novice programmer) I recently came across a problem with my custom

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(I’m a complete novice programmer)

I recently came across a problem with my custom CMS. I want to make it SEO friendly so I tried to echo out the title by the page loaded e.g.

www.blaa.com/index.php?page=about
//code here grabs the required page title from the mysql db $title = $row['title'];
<title><?php echo $title; ?></title>

I can’t see if this actually worked because when I view source it only displays this code:

<table>
<tr><td>Custom Module<br><br>

My custommodule cus any html goes in here

</td></tr>
<tr><td>Menu Body <br><br>
<a href='home.html'> home</a><br><a href='about page.html'> about page</a><br><br><br> </td></tr>
<tr><td>body<br>
cant believe im so a<br></div>
</td></tr>
<tr><td>Footer<br>
links go here to various pages<br></td></tr>
</table>

Is there a way to make all of the HTML code display in the view source?

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1 Answer

  1. Editorial Team

    You have to echo or print a variable to show it. You could also do a var_dump to check what the values are.

    <?php
$title = isset($_GET['title'])? $_GET['title'] : "No title.";
?>
<!DOCTYPE html>
<html>
<head>
  <title><?php echo htmlspecialchars($title); ?></title>
</head>

    I added htmlspecialchars to prevent script injection, I don’t know if it would work in the title tag but I added it just in case. Plus you should know whenever you write user input into your HTML page you should use htmlspecialchars to cancel out any html code & scripts.

    If your custom module is a load of HTML you wanted to display, you should use the inlude command:

    <body>
<?php include("path/to/custom_module.php"); ?>
</body>
</html>

# custom_module.php
<div>Hello, I'm the custom module.</div>
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