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Home/ Questions/Q 7458645
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T13:28:30+00:00 2026-05-29T13:28:30+00:00

I’m a designer trying to learn Jquery and I’m having a problem with a

  • 0

I’m a designer trying to learn Jquery and I’m having a problem with a current project. I need to be able to click a checkbox which in turn reveals a div. For each checkbox clicked a different div must be generated. I thought a switch function would do the trick but I haven’t been able to figure out how to implement it. Here is what I have so far:

<div">
    <input type="checkbox" id="test1" />
</div>
<div>
    <input type="checkbox" id="test2" />
</div>

<script type="text/javascript">

$(function () {
    $(':checkbox').click(function () {
        if ($(this).prop('checked', true)) {
            switch(this.id) {

                    case "test1";
                    var newDiv = $('<div><p>it worked!!</p></div>');

            break;

            case "test2";
                    var newDiv = $('<div><p>it worked again!!</p></div>');

            break;

            default;
            }
            newDiv.insertAfter($(this));

            $(this).after(newDiv);
        } else {
            $(this).next().filter('div').remove();
        }
    });
});

</script>

I hope someone can help!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T13:28:30+00:00Added an answer on May 29, 2026 at 1:28 pm

    So much wrong is so little…

    First problem is:

    switch(this.id)
    

    Which should be:

    switch($(this).attr('id')) // Need to wrap in jQuery object
    

    Also, your switch statement is wrong. Notice the : after case and not ; as you have.

    switch(n) {
        case 1:
            // Something
            break;
        case 2:
            // Something
            break;
        default:
            // Something
    }
    

    You need to declare newDiv outside the switch statement to access it later.
    Then, these one after another makes no sense, they do the same thing

    newDiv.insertAfter($(this)); // Keep this one
    $(this).after(newDiv);
    

    And, you have an extra " in your html, which was probably put by mistake…

    <div">
    

    Finally, you’re mixing double quotes and single quotes which will give you headaches later on. I suggest you choose one or the other.

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