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Home/ Questions/Q 3953266
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T01:57:16+00:00 2026-05-20T01:57:16+00:00

I’m a Grails beginner, so please be patient with me. Currently I’m having hard

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I’m a Grails beginner, so please be patient with me. Currently I’m having hard times manipulating file uploads. As far as I understand using request.getFile() I can easily get the stream of bytes. But before I do that, I want to check the following:

  • file name of the file being uploaded
  • file size of the file being uploaded
  • content/file type of the file being uploaded

How can this be done? Is it even possible before the file is uploaded to the server? I would like to block uploading of large files.

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  1. Editorial Team
    Editorial Team
    2026-05-20T01:57:17+00:00Added an answer on May 20, 2026 at 1:57 am

    All the information is contained in the CommonsMultipartFile object that you can cast your request parameter to.

    You can use it like that (in your controller)

    def uploaded = {
        def CommonsMultipartFile uploadedFile = params.fileInputName
        def contentType = uploadedFile.contentType 
        def fileName = uploadedFile.originalFilename
        def size = uploadedFile.size
    }
    

    As far as blocking large file uploads, this could be done by adding the following to your form:

    <INPUT name="fileInputName" type="file" maxlength="100000">
    

    but not all browsers will support it. The other limit is you container upload limit (see Tomcat configuration or whatever container you are using).

    Other than that, you have to check the size and reject it in the controller.

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