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Home/ Questions/Q 4569098
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T19:10:12+00:00 2026-05-21T19:10:12+00:00

I’m a little confused about how to use Tasks with conditional Continuations. If I

  • 0

I’m a little confused about how to use Tasks with conditional Continuations.

If I have a task, and then I want to continue with a tasks that handle success and error, and then wait on those to complete.

void FunctionThrows() {throw new Exception("faulted");}

static void MyTest()
{

    var taskThrows = Task.Factory.StartNew(() => FunctionThrows());

    var onSuccess = taskThrows.ContinueWith(
                          prev => Console.WriteLine("success"), 
                          TaskContinuationOptions.OnlyOnRanToCompleted);

    var onError = taskThrows.ContinueWith(
                          prev => Console.WriteLine(prev.Exception),
                          TaskContinuationOptions.OnlyOnFaulted);

    //so far, so good



    //this throws because onSuccess was cancelled before it was started
    Task.WaitAll(onSuccess, onError);
}

Is this the preferred way of doing task success/failure branching? Also, how am I supposed to join all these tasks, suppose I’ve created a long line of continuations, each having their own error handling.

  //for example
  var task1 = Task.Factory.StartNew(() => ...)
  var task1Error = task1.ContinueWith(  //on faulted
  var task2  = task1.ContinueWith(      //on success
  var task2Error = task2.ContinueWith(  //on faulted
  var task3 = task2.ContinueWith(       //on success
  //etc

Calling WaitAll on these invariably throws, because some of the continuations will be cancelled due to the TaskContinuationOptions, and calling Wait on a cancelled task throws.
How do I join these without getting the “A task was cancelled” exception”?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T19:10:13+00:00Added an answer on May 21, 2026 at 7:10 pm

    I think your main problem is that you’re telling those two tasks to “Wait” with your call to

    Task.WaitAll(onSuccess, onError);
    

    The onSuccess and onError continuations are automatically setup for you and will be executed after their antecedent task completes.

    If you simply replace your Task.WaitAll(...) with taskThrows.Start(); I believe you will get the desired output.

    Here is a bit of an example I put together:

    class Program
    {
        static int DivideBy(int divisor) 
        { 
          Thread.Sleep(2000);
          return 10 / divisor; 
        }
    
        static void Main(string[] args)
        {
            const int value = 0;
    
            var exceptionTask = new Task<int>(() => DivideBy(value));
    
            exceptionTask.ContinueWith(result => Console.WriteLine("Faulted ..."), TaskContinuationOptions.OnlyOnFaulted | TaskContinuationOptions.AttachedToParent);
            exceptionTask.ContinueWith(result => Console.WriteLine("Success ..."), TaskContinuationOptions.OnlyOnRanToCompletion | TaskContinuationOptions.AttachedToParent);
    
            exceptionTask.Start();
    
            try
            {
                exceptionTask.Wait();
            }
            catch (AggregateException ex)
            {
                Console.WriteLine("Exception: {0}", ex.InnerException.Message);
            }
    
            Console.WriteLine("Press <Enter> to continue ...");
            Console.ReadLine();
        }
    }
    
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