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Home/ Questions/Q 582749
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T14:43:13+00:00 2026-05-13T14:43:13+00:00

I’m a little confused on how to do this… I have a table that

  • 0

I’m a little confused on how to do this…

I have a table that has a series of rows, and within each cell, there are certain form elements. I’m trying to get the value from the “code” input field from the last row only, and am having trouble with the syntax…

Simplified table looks like this:

<table id="table1">
<tr><td><input type="hidden" name="code" value="XFT" /></td></tr>
<tr><td><input type="hidden" name="code" value="ETY" /></td></tr>
<tr><td><input type="hidden" name="code" value="DHQ" /></td></tr>
</table>

And, here’s the jquery that doesn’t work…

if($('#cont')) {
            $("#cont').live('click', function(event) {
                var tr = $('#wr-viewcarttable tr:last');
                var itemcode = $(tr > 'input[name="code"]').val();
                window.location = "/search?p="+itemcode;
            });
        }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T14:43:13+00:00Added an answer on May 13, 2026 at 2:43 pm

    Try this:

    $('table#table1 tr:last input[name=code]').val();
    

    Or, adjusted to your code:

    $('#cont').live('click', function(event) {
        var tr = $('#wr-viewcarttable tr:last');
        var itemcode = tr.find('input[name=code]').val();
        window.location = "/search?p="+itemcode;
    });
    

    You have two errors in your code, you have mismatched quotes in the $("#cont') part and your input search is wrong. What you have now is:

    $(tr > 'input[name="code"]').val();
    

    As the > is outside quotes, it is not a string, but a comparison operator, which now compares tr to 'input[name="code"]'. Comparison operators always return boolean values (true or false), so you’re effectively doing this:

    $(true).val();
    

    Which doesn’t make much sense. If you have a jQuery object, you can use the find method to find any children of that object, or alternatively pass the element as context to the $() function. So these two will work and are equal:

    tr.find('input[name=code]').val();
    $('input[name=code]', tr).val();
    

    There’s actually no reason to save the tr to it’s own variable in your case, as you can get the value in just one declaration, as shown above.

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