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Home/ Questions/Q 615947
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T18:16:27+00:00 2026-05-13T18:16:27+00:00

I’m a little confusing when try something like this b = [lambda x:x**i for

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I’m a little confusing when try something like this

b = [lambda x:x**i for i in range(11)]

When I then try b[1](2) I have 1024 as a result that is wrong. But when I write so

b = [(lambda i: lambda x:x**i)(i) for i in range(11)]

all is OK

>>> b[1](2)
2
>>> b[5](2)
32

It works fine but what’s wrong in first code?

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  1. Editorial Team
    Editorial Team
    2026-05-13T18:16:28+00:00Added an answer on May 13, 2026 at 6:16 pm

    This is due to how closures in Python work.

    The loop changes the value in the scope that all the functions share. Move generation of the function into a separate scope, i.e. function.

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