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I’m a MATLAB beginner. Here’s the problem:
>> a = floor(7/2.5)
a =
2.00
>> b = rem(7,2.5)
b =
2.00
>> c = floor(b/2)
c =
0
c should be 1, right? Why is it 0???
It is different when b = 2 is entered directly as follows:
>> b = 2
b =
2.00
>> c = floor(b/2)
c =
1.00
In two words: truncation errors.
You’re right, c should be 1.0 in exact arithmetic. However, since you used a float in the arguments of rem, you get the answer as a float. Apparently, b is not exactly 2, but 2.0, which means that it is a double very close to 2. Therefore, b/2 becomes the double 1.0, apparently in this case its value is slightly less than one, giving you a 0 as the integer value. If you want to prevent this, use both floor and ceil, and compare the values.
If you want to convert the answer to integer, just use round instead of floor.