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Home/ Questions/Q 6880489
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T04:58:50+00:00 2026-05-27T04:58:50+00:00

I’m a newbie in SQL server. I’ve the following table: id dayoftheweek timeoftheday 1

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I’m a newbie in SQL server.

I’ve the following table:

id  dayoftheweek    timeoftheday
1   mondayOpen  0:00 
1   mondayClose 23:59
1   tuesdayOpen 0:00
1   tuesdayClose    23:59
1   wednesdayOpen   0:00
1   wednesdayClose  23:59
1   thursdayOpen    0:00
1   thursdayClose   23:59
1   fridayOpen  0:00
1   fridayClose 23:59
1   saturdayOpen    0:00
1   saturdayClose   23:59
1   sundayOpen  0:00
1   sundayClose 23:59

I want the following:

     id day     open   close
     1  monday  0:00   23:59
     2  tuesday 0:00   23:59

I don’t know if i need to write a sproc (T-SQL) or if there are any built-in keywords in SQL , using which i can get the output i desire. I cannot create a new table but views, sprocs are allowed in my existing schema.

Please help me.

TIA

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  1. Editorial Team
    Editorial Team
    2026-05-27T04:58:51+00:00Added an answer on May 27, 2026 at 4:58 am

    The table structure there is horrid, I’d do anything you could to get away from it. That said mssql has a few substring functions your can use.

    select dayoftheweek, timeoftheday 'open'
    from uglytable
    where right(dayofweek,4) = 'Open'
    

    This will give you all records that are open. We’ll do the same thing to get all closed records in a sec. That will get by the challenge of reading open vs closed

    Second issue to address is picking the ‘day’ column out of that text. Every day ends in y and contains no other ‘y”s in it, so we can use charindex

    lil disclaimer…I don’t have a mssql db available for testing, so I might be a char off here and there.

     select charindex('y',dayoftheweek)
    

    That will return the location in the string of the ‘y’ character.

    Mondayopen has a y on the 6th character

    select left('mondayopen',6)
    

    That would return the left 6 chars of mondayOpen or mondayClose. Put the two together:

    select left(dayoftheweek,charindex('y',dayoftheweek))
    

    Hope I got that right…it should turn mondayopen and mondayclose to monday. Put the two together:

    select left(dayoftheweek,charindex('y',dayoftheweek)) dayofweek, timeoftheday 'open'
    from uglytable
    where right(dayofweek,4) = 'Open'
    

    This should now return the dayofweek without the ‘open’ or ‘close’ along with the open time. Turn it into a subquery, join it to the close subquery and put together:

    select open.dayofweek, open.open,close.close
    from
    (select left(dayoftheweek,charindex('y',dayoftheweek)) dayofweek, timeoftheday 'open'
    from uglytable
    where right(dayofweek,4) = 'Open')  open
    inner join
    (select left(dayoftheweek,charindex('y',dayoftheweek)) dayofweek, timeoftheday 'close'
    from uglytable
    where right(dayofweek,5) = 'Close')  close
    on open.dayofweek = close.dayofweek
    

    Hope I don’t have syntax errors in there, nothing to test it on and might have a typo ^^

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