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Home/ Questions/Q 1009047
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T08:51:56+00:00 2026-05-16T08:51:56+00:00

I’m a newbie to the jQuery UI plugin and I’m building a demo application

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I’m a newbie to the jQuery UI plugin and I’m building a demo application to test my knowledge. I’m using the radio button add-on and I can’t seem to get it working. I have the following line in a function called when the body loads:

$("#buttonSetDiv").buttonset();

I’m also including the CSS and JS correctly, like so:

<style src="jquery-ui-1.8.4.custom/css/ui-darkness/jquery-ui-1.8.4.custom.css"></style>
<script type="text/javascript" src="jquery-1.4.js"></script>
<script type="text/javascript" src="jquery-ui-1.8.4.custom/js/jquery-ui-1.8.4.custom.min.js"></script>

… and the actual HTML looks like this:

<form name="radios" id="myForm">
<div id="buttonSetDiv">
<input type="radio" name="group1" value="posts" id="radio1" checked onchange="valueChanged()"> <label for="radio1">Posts</label>
<input type="radio" name="group1" value="members" onchange="valueChanged()" id="radio2">
<label for="radio2">Members</label>
</div>
</form> 

… but for some reason, with this seemingly correct implementation, I’m still getting normal-looking radio buttons. I’d like to achieve this effect:

picture

Does anyone have an answer here? Thanks a ton in advance. 🙂

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  1. Editorial Team
    Editorial Team
    2026-05-16T08:51:56+00:00Added an answer on May 16, 2026 at 8:51 am

    Your <input> is missing a closing quote on the id="radio2", so this:

    <input type="radio" name="group1" value="members" onchange="valueChanged()" id="radio2>
    

    Should be:

    <input type="radio" name="group1" value="members" onchange="valueChanged()" id="radio2">
    

    This is throwing off at least Chrome in recognizing it correctly, you can try the fixed version here.

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