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Home/ Questions/Q 8992899
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T23:03:59+00:00 2026-06-15T23:03:59+00:00

I’m actually porting a Linux app to Mac OS X. My problem is that

  • 0

I’m actually porting a Linux app to Mac OS X. My problem is that I can access the variables but not the pointers.

I declared the variables in the main.h this way:

uint64_t test;
uint64_t *test2;

In the mylib.h:

extern uint64_t test;
extern uint64_t *test2;

and in mylib.c I access the variables this way:

printf("%llu\n",test);
printf("%llu\n",*test2);

The first printf() doesn’t have any problems but the second gives me this error:

Program received signal EXC_BAD_ACCESS, Could not access memory.
Reason: KERN_INVALID_ADDRESS at address: 0x0000000000000008

Does anybody know why this happened?

My ggc command line has the following flags:

gcc -Wall -g -fPIC -c main.c gcc -shared -Wl,-undefined,dynamic_lookup -o mylib.so mylib.o
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  1. Editorial Team
    Editorial Team
    2026-06-15T23:04:00+00:00Added an answer on June 15, 2026 at 11:04 pm

    Just for someone with a similar problem:

    I decided to work with getter & setter because there wasn’t problems to access the function of the main program with a dynamic library just the variables.

    in mylib.c :

    test2 = getTest();
    

    in main.c :

    uint64_t* getTest(){
        return &test;
    }
    

    Update

    I finally found a way around this getter & setter. The problem you are facing is that you’re defining your variable twice, in my case this happened during a misunderstanding of the extern keyword. To solve your problem you need to declare the variables as extern in your main.h e.g.:

    extern uint64_t test;
    extern uint64_t *test2;
    

    Next step is to define the variables in your main.c e.g.:

    int main(...) {
        test = 1;
        test2 = &test;
    }
    

    And finally remove the extern declaration from your mylib.h

    The following SO post led to my solution: link

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