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Asked: 2026-05-28T05:00:04+00:00

I’m after the following XML serialization output: <?xml version=1.0?> <Message> <Version>1.0</Version> <Body> <ExampleObject xmlns:xsi=http://www.w3.org/2001/XMLSchema-instance

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I’m after the following XML serialization output:

<?xml version="1.0"?>
<Message>
  <Version>1.0</Version>
  <Body>
    <ExampleObject xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
      <EmampleOne>Hello!</EmampleOne>
    </ExampleObject>
  </Body>
</Message>

I have the following classes:

[Serializable]
    public class Message<T>
    {
        public string Version { get; set; }
        public T Body { get; set; }
    }

[Serializable]
public class ExampleObject
{
    public string EmampleOne { get; set; }
}

If I serialize them separately I get:

<?xml version="1.0"?>
<Message>
  <Version>1.0</Version>
  <Body>
    <EmampleOne>Hello!</EmampleOne>
  </Body>
</Message>

And:

<?xml version="1.0"?>
<ExampleObject>
  <EmampleOne>Hello!</EmampleOne>
</ExampleObject>

So as shown above I’m wanting the inner body to contain the class name <ExampleObject>.

I use generics as I need to have different Message Body’s, I serialize with the code:

var obj = new Message<ExampleObject>
{
    Version = "1.0",
    Body = example
};

var serializer2 = new XmlSerializer(typeof (Message<ExampleObject>));
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1 Answer

  1. Editorial Team

    As @Marc Gravell suggested in his comment, you can use XmlAttributeOverrides:

    var xmlOverrides = new XmlAttributeOverrides();
var attributes = new XmlAttributes();
attributes.XmlElements
     .Add(new XmlElementAttribute("ExampleObject", typeof (ExampleObject)));
xmlOverrides.Add(typeof(Message<ExampleObject>), "Body", attributes);

var serializer2 = new XmlSerializer(typeof(Message<ExampleObject>), xmlOverrides);
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