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Home/ Questions/Q 7158651
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T13:06:07+00:00 2026-05-28T13:06:07+00:00

I’m allowing user-input css. What is a light and performant way to validate that

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I’m allowing user-input css.

What is a light and performant way to validate that css on the client side?

I’m looking for a javascript solution. I don’t want to send the css off to some remote server or anything.

Context:
Allowing user css

Thanks.

Edit: NVM on this question. I started using a server-side validator:
https://github.com/chriso/node-validator

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  1. Editorial Team
    Editorial Team
    2026-05-28T13:06:07+00:00Added an answer on May 28, 2026 at 1:06 pm
    function getDefinedCss(s){
        if(!document.styleSheets) return '';
        if(typeof s== 'string') s= RegExp('\\b'+s+'\\b','i'); // IE capitalizes html selectors 
    
        var A, S, DS= document.styleSheets, n= DS.length, SA= [];
        while(n){
            S= DS[--n];
            A= (S.rules)? S.rules: S.cssRules;
            for(var i= 0, L= A.length; i<L; i++){
                    tem= A[i].selectorText? [A[i].selectorText, A[i].style.cssText]: [A[i]+''];
                    if(s.test(tem[0])) SA[SA.length]= tem;
            }
        }
        return SA.join('\n\n');
    }
    
    // Then you check the class if exists by calling getDefinedCss('myclassname')
    
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