I’m am unsure on how to move part of my code into a class.
<?php
class InfoTest {
private $info_results;
public function __construct() {
$dbc = get_dbc();
$info = $dbc->query ("SELECT info_id, info_title FROM text");
if ($dbc->error) {
printf("Error: %s\n", $dbc->error);
}
while ($info_row = $info->fetch_array())
{
$info_results[]= $info_row;
}
$info->free();
$this->info_results = $info_results;
}
public function setInfo() {
$this->info_results = $info_results;
}
public function getInfo() {
return $this->info_results;
}
public function __destruct() {
}
}
?>
<?php
$display = new InfoTest();
foreach ($display->getInfo() as $info_row) {
?>
<!-- html -->
<?php echo $info_row['info_title']."</a><br />"; ?>
<!-- html -->
Sub-Info:
<?php
$dbc = get_dbc();
$si_title = $dbc->query ("SELECT info_title FROM text WHERE info_id = ".$info_row['info_id']."");
if ($dbc->error) {
printf("Error: %s\n", $dbc->error);
}
$num =$si_title->num_rows;
$count = 0;
while ($sub_info = $si_title->fetch_array())
{
$sub_info_title = $sub_info['info_title'];
if ($count!=$num-1)
{
echo $sub_info_title." , ";
$count++;
}
else echo $sub_info_title;
}
?>
<!-- html -->
<?php } ?>
I’m unsure how to move the Sub-Info(code after Sub-Info:) into a class. Does it go in the same class as InfoTest, a class of its own, or doesn’t go into a class at all?
Sub-Info Code:
<?php
$dbc = get_dbc();
$si_title = $dbc->query ("SELECT info_title FROM text WHERE info_id = ".$info_row['info_id']."");
if ($dbc->error) {
printf("Error: %s\n", $dbc->error);
}
$num =$si_title->num_rows;
$count = 0;
while ($sub_info = $si_title->fetch_array())
{
$sub_info_title = $sub_info['info_title'];
if ($count!=$num-1)
{
echo $sub_info_title." , ";
$count++;
}
else echo $sub_info_title;
}
?>
In your class you have already all information. So an alternative to a sql-query could be an additional method, which searches all titles with a special id in the private field
info_results. E.g.:Your Sub-Info Code is then: