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Home/ Questions/Q 707257
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T04:15:26+00:00 2026-05-14T04:15:26+00:00

I’m apparently laboring under a poor understanding of Python scoping. Perhaps you can help.

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I’m apparently laboring under a poor understanding of Python scoping. Perhaps you can help.

Background:
I’m using the

if __name__ == "__main__"

construct to perform “self-tests” in my module(s). Each self test makes calls to the various public methods and prints their results for visual checking as I develop the modules.

To keep things “purdy” and manageable, I’ve created a small method to simplify the testing of method calls:

def pprint_vars(var_in):
    print("%s = '%s'" % (var_in, eval(var_in)))

When

foo = "bar"

Calling pprint_vars with:

pprint_vars('foo')

prints:

foo = 'bar'

All fine and good.

Problem statement:
Not happy to just KISS, I had the brain-drizzle to move my handy-dandy ‘pprint_vars’ method into a separate file named ‘debug_tools.py’ and simply import ‘debug_tools’ whenever I wanted access to ‘pprint_vars’.

Here’s where things fall apart. I would expect

import debug_tools

foo = bar
debug_tools.pprint_vars('foo')

to continue working its magic and print:

foo = 'bar'

Instead, it greets me with:

NameError: name 'some_var' is not defined

Irrational belief:
I believed (apparently mistakenly) that import puts imported methods (more or less) “inline” with the code, and thus the variable scoping rules would remain similar to if the method were defined inline.

Plea for help:
Can someone please correct my (mis)understanding of scoping regards imports?

Thanks,
JS

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T04:15:27+00:00Added an answer on May 14, 2026 at 4:15 am

    In python each file is its own namespace. A function, when called, resolves its variables in the following order:

    1. local variables (that includes captured variables or in a closure)
    2. (module) global variables
    3. builtins

    You can use the (interpreter specific) inspect module to navigate the callstack as a list of frames. Since a frame knows its locals, globals, builtins and parent frame, you can ‘see’ the interpreter through the eyes of your caller like this (please only use for debugging):

    import inspect
    def log_var(name):
        f = inspect.currentframe().f_back
        if name in f.f_locals:
            print "local `%s` = %r" % (name, f.f_locals[name])
        elif name in f.f_globals:
            print "global `%s` = %r" % (name, f.f_globals[name])
        elif name in f.f_builtins:
            print "builtin `%s` = %r" % (name, f.f_builtins[name])
        else:
            print "`%s` not found" % name
    
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