Question

I’m aware of all the arguments against conditional compilation in Java. In this specific case, I’d only want to have a small IF in order to be able to test whether the code runs in Eclipse or not. The reason for this is that when I override a View to use my special processing, Eclipse in some cases cannot compile the modified View and display it in the IDE (there are many cases resulting in this behavior but a specific one is when the code refers to a JNI library that Eclipse, obviously, cannot execute).

Right now I’m using

if (!Build.DEVICE.startsWith("generic"))
 // do something

and it works but I don’t really like doing a string comparison every single time in an onDraw(), for instance. I’d need a simpler way, a cheaper condition to see if I’m in Eclipse and avoid some actions then.

Edit: To be clearer, I’m looking for a possible Java/Android/Eclipse equivalent of C#’s Component.DesignMode property.

Answer 1

The best I could come up with so far is:

import android.os.Build;

public class IDE {
  private static IDE instance = null;
  protected boolean designMode = false;

  private IDE() {
    designMode = Build.DEVICE.startsWith("generic");
  }

  public static IDE getInstance() {
    if (instance == null)
      instance = new IDE();
    return instance;
  }

  public static boolean DesignMode() {
    return getInstance().designMode;
  }
}

This is a singleton class that encapsulates the check and can be queried as:

if (!IDE.DesignMode())
  // do something