Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 9151681
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 17, 20262026-06-17T11:51:42+00:00 2026-06-17T11:51:42+00:00

I’m basically attempting to use the NOT IN function twice during a mySQL query

  • 0

I’m basically attempting to use the NOT IN function twice during a mySQL query
My NEW current query is as followed

SELECT `o`.`id`, `o`.`name`, `o`.`url`, `o`.`type`, `o`.`desc` FROM `offers` as `o` 
WHERE `o`.country_iso = '$country_iso' AND `o`.`id` not in 
(select distinct(offer_id) from conversions where ip = '$_SERVER[REMOTE_ADDR]' 
and converted != '0') AND `o`.`id` not in 
(select `offer_id` from `aff_disabled_offers` where `offer_id` = 'o.id' 
and `user_id` = '1') ORDER by rand() LIMIT $limit

The query works but for some reason it’s completely ignoring this

AND `o`.`id` not in 
(select `offer_id` from `aff_disabled_offers` where `offer_id` = 'o.id') 
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-17T11:51:43+00:00Added an answer on June 17, 2026 at 11:51 am

    You need to specify an operator between your conditions, such as AND or OR. You also need a valid query inside the NOT IN clause.

    SELECT `o`.`id`, `o`.`name`, `o`.`url`, `o`.`type`, `o`.`desc` 
    FROM `offers` as `o` 
    WHERE `o`.country_iso = '$country_iso' 
    AND `o`.`id` not in (select distinct(offer_id)
                         from converstions where
                         from conversions 
                         where ip = '$_SERVER[REMOTE_ADDR]' 
                         and converted != '0')
    AND `o`.`somevar` not in (select `somevar` from 
                              `sometable` where `offer_id` = 'o.id')
    ORDER by rand() LIMIT 0,6
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I want use html5's new tag to play a wav file (currently only supported
I need a function that will clean a strings' special characters. I do NOT
I have a string like this: La Torre Eiffel paragonata all’Everest What PHP function
Basically, what I'm trying to create is a page of div tags, each has
link Im having trouble converting the html entites into html characters, (&# 8217;) i
I am confused How to use looping for Json response Array in another Array.
I am trying to understand how to use SyndicationItem to display feed which is
I'm parsing an RSS feed that has an ’ in it. SimpleXML turns this
I've tracked down a weird MySQL problem to the two different ways I was
I'm trying to select an H1 element which is the second-child in its group

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.