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Home/ Questions/Q 7911349
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T13:12:46+00:00 2026-06-03T13:12:46+00:00

I’m brand new to lua and LÖVE. I am trying to do a simple

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I’m brand new to lua and LÖVE.

I am trying to do a simple counting of numbers with a small delay, so that the user can see the count happen (instead of the code simply counting and then displaying the finished count)

I have the following code:

function love.draw()
    love.graphics.print("Welcome again to a simple counting sheep excercise.", 50, 50)

    i = 20
    ypos = 70

    while i > 0 do

        love.graphics.print("Number: " .. i .. ".", 50, ypos)
        love.timer.sleep(1)
        i = i - 1
        ypos = ypos + 12


    end

end

But when I run it, it just hangs for ~20 seconds and then displays the completed count. How do I make it pause briefly between each iteration? I suspect that the problem is that the draw function is called once, and so it completes all of its work before displaying.

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  1. Editorial Team
    Editorial Team
    2026-06-03T13:12:49+00:00Added an answer on June 3, 2026 at 1:12 pm

    love.draw() is called many times per second, so you shouldn’t really sleep, because it causes the entire application to hang.

    Instead, use love.update() to update the state of the application based on the current time (or based on time delta).

    For example, I would express what you’re trying to do as follows:

    function love.load()
       initTime = love.timer.getTime()
       displayString = true
    end
    
    function love.draw()
        love.graphics.print("Welcome again to a simple counting sheep excercise.", 50, 50)
        if displayString then
            love.graphics.print("Number: " .. currentNumber .. ".", 50, currentYpos)
        end
    end
    
    function love.update()
        local currentTime = love.timer.getTime()
        local timeDelta = math.floor(currentTime - initTime)
        currentNumber = 20 - timeDelta
        currentYpos = 70 + 12 * timeDelta
        if currentNumber < 0 then
            displayString = false
        end
    end
    

    First I find the initial time, and then I calculate the number and the position based on the time difference from the initial time. The difference is in seconds, which is why I call math.floor to make sure I get an integer.

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