Question

I’m building a dropdown menu populated from a php range of numbers. My code works so far. Here’s how I’ve written it so far:

      <?php
    echo "<select name='Strength_Pts2' id='Strength_Pts2'>";
    foreach($PotRange as $AttributesAvailable) 
    {
        echo "<option value='$AttributesAvialabe'>$AttributesAvailable</option>";
    }
    echo "</select>";
?>

Now, I’d like to add an If/Then condition to the menu, so under certain circumstances the user will only get an option of ‘0’ instead of the whole range. Here’s what I coded:

         <?php
    echo "<select name='Strength_Pts2' id='Strength_Pts2'>";
    if ( 1 == 1 ) {
foreach($PotRange as $AttributesAvailable) 
    {
        echo "<option value='$AttributesAvialabe'>$AttributesAvailable</option>";
    }
    else
echo "<option value='0'>0</option>";
}
echo "</select>";
?> 

I’ve tried it with and without a ; after the last }. I get Parse error: syntax error, unexpected T_ELSE on line 531.

Can anybody help out with what I’m doing wrong?

Thanks in advance, -CB

Answer 1

You forgot some curly braces, use the following:

<?php
  echo "<select name='Strength_Pts2' id='Strength_Pts2'>";
    if ( 1 == 1 ) {
      foreach($PotRange as $AttributesAvailable) {
        echo "<option value='$AttributesAvialabe'>$AttributesAvailable</option>";
      }
    } else {
      echo "<option value='0'>0</option>";
    }
  echo "</select>";
?>